Fast Division
 "SRT" division carry propagation free To avoid the delay of the carry propagation, the following applet uses a stack of borrow-save "BS" adders/subtractors. The "tail" cell, variant of the "SC" and "AS" cells, is controlled by two bits and executes one of the three following operations: an addition : Rj-1 = Rj + 2j-1 * D a subtraction : Rj-1 = Rj – 2j-1 * D an identity : Rj-1 = Rj This operation is selected according to the sign of the partial remainders Rj. To always know precisely this sign would require the examination of all the remainder's digits. It suffices to check only three (named hereafter). Moreover, the position of the three digits is known: the least significant one is aligned with the most significant non-zero bits of D. To nail down this digit position, D is "normalized", that is the position of its first '1' bit is fixed. Let us call this position 0 and accordingly D's first bit d0. Thus d0= '1'. For an n-bit divider, 2n-2–1 < D < 2n-1 . The vertical arrow "view" next to the button displays digits or bits or moves the decimal point right after the most significant digit of D as with a mantissa or after the least significant digit as with an integer.
 Conditional carry-propagation-free adder/subtractor A "conditional adder/subtractor" outputs S from one of the three following equations: if q = '-1' then S = R + D ; if q = '0' then S = R ; if q = '1' then S = R – D ; Each "tail" cell carries out a one-bit addition/subtraction. The carry is not propagated to the "tail" cell at left but fed down directly to the "tail" cell below (next row). The delay is independent from the number of digits.
 The "conditional adder/subtractor" function is abstracted by its transfer function called "Robertson's diagram". To converge the division imposes moreover that -2*D £ R £ 2*D. If -D £ R £ 2 then S has two possible values.
 "tail"cell of the "SRT" divider Check your knowledge of the "tail" cell truth table . if q = '-1' then 2*s1 – s0 = d0 + r0 ; // addition if q = '0' then 2*s1 – s0 = r0 ; // identity if q = '1' then 2*s1 – s0 = 1 – d0 + r0 ; // subtraction
 "head" cell of the "SRT" divider Let be = r2* 4 + r1* 2 + r0 and = s2* 4 + s1* 2 + s0 the input and output values of the "head" cell. if < 0 then { = +1 ; q = '-1' ; } // addition if = 0 then { = ; q = '0' ; } // identity if > 0 then { = – 2 ; q = '1'; } // subtraction In an actual division (without overflow), output s2 will always be 0. The overflow digit s2 is used in the "double division" .
 Necessity of the '0' in the quotient Q If R > 0 an addition must not be performed and if R < 0 a subtraction must not be performed, or else the division overflows. When = 0, the sign of R is not known since to know it would potentially require the examination of all R's digits, so neither an addition nor a subtraction can be performed when = 0 and q have to be '0' .
 Necessity of the normalization of the divider D For the "head" cell, a remainder R is small if = 0 , in other words if -1 < R < 1. In this case R keeps its value that may go outside the " Robertson's diagram" if 1 > D. Consequently 1 £ D. D's maximum value 2 is set only to simplify the head's equations.
 "SRT" division with divider range reduction The previous division is simple because the fist bit d0 of the divider D is always '1'. It may be even further simplified if the two first bits d0 and d1 of the divider D are reduced to "1 0" thanks to the operation : if d0 then { D' = D*3/4 ; A' = A*3/4 } else { D' = D ; A' = A } . This multiplication of both A and D by the same constant does not affect the quotient Q, but on the other hand the final remainder R is also multiplied. For an n-bit divider, 2n-1–1 < D < 2n-1 + 2n-2 .
 Head cell of the "SRT" divider with range reduction Let = r0 + r1* 0.5 be the "head" cell input value. if > 0.5 then { s1 = – 1.5 ; q = '+1'; } if = 0.5 then { s1 = 0 ; q = '- 0' ; } if = 0 then { s1 = 0 ; q = '+ 0' ; } or { s0 = - 0.5 ; q = '- 0' ; } if = - 0.5 then { s1 = - 0.5 ; q = '+ 0' ; } if < - 0.5 then { s1 = + 1 ; q = '-1' ; } Here the difference between the two 0 representations for q : '+ 0' and '- 0' matters.
 Quotient converter The quotient Q is in "BS" redundant notation. The conversion into a conventional binary representation is obtained thanks to an adder (in fact a subtractor). For the subtraction, '0' gives 'P', '1' gives 'G' et '-1' gives 'K'. Since the digits qj are obtained sequentially, most significant digit first, the conversion can be carried out in parallel with the quotient digits selection by the "head" cells.
 Let "Ratio" be the "head" cell and "BK" cell delays ratio. The higher this ratio, the more delay available thus the simpler the converter. But the higher this ratio, the less delay is gained by the concurrence of the converter.
 Quotient correction In order to subtract the logic complement plus 1 must be added. Nevertheless if the dividend A and the divisor D are both positive (which is the case in floating point) and the final remainder R is negative then the quotient Q is too large and must be corrected by not adding 1. So the complement of the remainder R sign must be added.. Remember that adding 1 changes the 'P' into '1' and adding 0 changes the 'P' into '0'.
 Divider design The quotient Q digits are redundant and symmetrical. They are defined by the radix and the maximum digit value. This applet let you choose the set of quotient digit values; then the number of bits from divider D and number of digit from partial remainder R that must be taken into account for the selection of the quotient digit value.

The leftmost button processes forth to the next or back to the previous step.

• 1- Robertson's diagram, plotting the next partial remainder according to the current partial remainder. D appears implicitly on the axis.
• 2- Symmetrical "PD plot" for D in the range [1 .. 2 [. The "PD plot" permits to select the value of a digit q according to P and D.
• 3- Half "PD plot", upper part of the preceding one. The lower part is obtained by changing the sign.
• 4- Discretised half "PD plot". The number of D bits taken into account gives the abscissa discretisation, while the number of P digits gives the ordinate discretisation.
Fixing this number of bits/digits will determine whether a boundary can separate the different values of q.
• 5- Half truth table for the half "PD plot". The other part is obtained by the sign of Q.